only show one status if the thread is not cached
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25dfb99bb4
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@ -86,13 +86,20 @@ async function getStatusThread (instanceName, statusId) {
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let keyRange = createThreadKeyRange(statusId)
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threadsStore.getAll(keyRange).onsuccess = e => {
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let thread = e.target.result
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let res = new Array(thread.length)
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thread.forEach((otherStatusId, i) => {
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fetchStatus(statusesStore, accountsStore, otherStatusId, status => {
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res[i] = status
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if (thread.length) {
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let res = new Array(thread.length)
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callback(res)
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thread.forEach((otherStatusId, i) => {
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fetchStatus(statusesStore, accountsStore, otherStatusId, status => {
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res[i] = status
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})
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})
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})
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callback(res)
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} else {
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// thread not cached; just make a "fake" thread with only one status in it
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fetchStatus(statusesStore, accountsStore, statusId, status => {
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callback([status])
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})
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}
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}
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})
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}
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